Text substitution (reading from file and saving to the same file) on linux with sed

I want to read the file "teste", make some "find&replace" and overwrite "teste" with the results. The closer i got till now is:

$cat teste
I have to find something
This is hard to find...
Find it wright now!
$sed -n 's/find/replace/w teste1' teste
$cat teste1
I have to replace something
This is hard to replace...

If I try to save to the same file like this:

$sed -n 's/find/replace/w teste' teste

or:

$sed -n 's/find/replace/' teste > teste

The result will be a blank file...

I know I am missing something very stupid but any help will be welcome.

---

UPDATE: Based on the tips given by the folks and this link: here's my updated code:

sed -i -e 's/find/replace/g' teste 

0

7 Answers

On Linux, sed -i is the way to go. sed isn't actually designed for in-place editing, though; historically, it's a filter, a program which edits a stream of data in a pipeline, and for this usage you would need to write to a temporary file and then rename it.

The reason you get an empty file is that the shell opens (and truncates) the file before running the command.

4

You want: sed -i 's/foo/bar/g' file

1

You want to use "sed -i". This updates in place.

In-place editing with perl

perl -pi -w -e 's/foo/bar/g;' file.txt

or

perl -pi -w -e 's/foo/bar/g;' files*

for many files

The ed solution is:

ed teste <<END
1,$s/find/replace/g
w
q
END

Or without the heredoc

printf "%s\n" '1,$s/find/replace/g' w q | ed teste

0

Actually, if you use -i flag, sed will copy the original line you edit.

So this might be a better way:

sed -i -e 's/old/new/g' -e '/new/d' file

0

There is a useful sponge command.

sponge soaks up all its input before opening the output file.

$cat test.txt | sed 's/find/replace/w' | sponge test.txt

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