Initialising a multidimensional array in Java

What is the correct way to declare a multidimensional array and assign values to it?

This is what I have:

int x = 5;
int y = 5;
String[][] myStringArray = new String [x][y];
myStringArray[0][x] = "a string";
myStringArray[0][y] = "another string";

0

7 Answers

Java doesn't have "true" multidimensional arrays.

For example, arr[i][j][k] is equivalent to ((arr[i])[j])[k]. In other words, arr is simply an array, of arrays, of arrays.

So, if you know how arrays work, you know how multidimensional arrays work!

---

Declaration:

int[][][] threeDimArr = new int[4][5][6];

or, with initialization:

int[][][] threeDimArr = { { { 1, 2 }, { 3, 4 } }, { { 5, 6 }, { 7, 8 } } };

---

Access:

int x = threeDimArr[1][0][1];

or

int[][] row = threeDimArr[1];

---

String representation:

Arrays.deepToString(threeDimArr);

yields

"[[[1, 2], [3, 4]], [[5, 6], [7, 8]]]"

Useful articles

• Java: Initializing a multidimensional array
• Java: Matrices and Multidimensional Arrays

4

Try replacing the appropriate lines with:

myStringArray[0][x-1] = "a string";
myStringArray[0][y-1] = "another string";

Your code is incorrect because the sub-arrays have a length of y, and indexing starts at 0. So setting to myStringArray[0][y] or myStringArray[0][x] will fail because the indices x and y are out of bounds.

String[][] myStringArray = new String [x][y]; is the correct way to initialise a rectangular multidimensional array. If you want it to be jagged (each sub-array potentially has a different length) then you can use code similar to this answer. Note however that John's assertion that you have to create the sub-arrays manually is incorrect in the case where you want a perfectly rectangular multidimensional array.

0

You can also use the following construct:

String[][] myStringArray = new String [][] { { "X0", "Y0"}, { "X1", "Y1"}, { "X2", "Y2"}, { "X3", "Y3"}, { "X4", "Y4"} };

0

You can declare multi dimensional arrays like :

// 4 x 5 String arrays, all Strings are null
// [0] -> [null,null,null,null,null]
// [1] -> [null,null,null,null,null]
// [2] -> [null,null,null,null,null]
// [3] -> [null,null,null,null,null]
String[][] sa1 = new String[4][5];
for(int i = 0; i < sa1.length; i++) { // sa1.length == 4 for (int j = 0; j < sa1[i].length; j++) { //sa1[i].length == 5 sa1[i][j] = "new String value"; }
}
// 5 x 0 All String arrays are null
// [null]
// [null]
// [null]
// [null]
// [null]
String[][] sa2 = new String[5][];
for(int i = 0; i < sa2.length; i++) { String[] anon = new String[ /* your number here */]; // or String[] anon = new String[]{"I'm", "a", "new", "array"}; sa2[i] = anon;
}
// [0] -> ["I'm","in","the", "0th", "array"]
// [1] -> ["I'm", "in", "another"]
String[][] sa3 = new String[][]{ {"I'm","in","the", "0th", "array"},{"I'm", "in", "another"}};

Multidimensional Array in Java

Returning a multidimensional array

Java does not truely support multidimensional arrays. In Java, a two-dimensional array is simply an array of arrays, a three-dimensional array is an array of arrays of arrays, a four-dimensional array is an array of arrays of arrays of arrays, and so on...

We can define a two-dimensional array as:

1. int[ ] num[ ] = {{1,2}, {1,2}, {1,2}, {1,2}}

2. int[ ][ ] num = new int[4][2]

   num[0][0] = 1;
   num[0][1] = 2;
   num[1][0] = 1;
   num[1][1] = 2;
   num[2][0] = 1;
   num[2][1] = 2;
   num[3][0] = 1;
   num[3][1] = 2;

   If you don't allocate, let's say num[2][1], it is not initialized and then it is automatically allocated 0, that is, automatically num[2][1] = 0;

3. Below, num1.length gives you rows.

4. While num1[0].length gives you the number of elements related to num1[0]. Here num1[0] has related arrays num1[0][0] and num[0][1] only.

5. Here we used a for loop which helps us to calculate num1[i].length. Here i is incremented through a loop.

   class array
   { static int[][] add(int[][] num1,int[][] num2) { int[][] temp = new int[num1.length][num1[0].length]; for(int i = 0; i<temp.length; i++) { for(int j = 0; j<temp[i].length; j++) { temp[i][j] = num1[i][j]+num2[i][j]; } } return temp; } public static void main(String args[]) { /* We can define a two-dimensional array as 1. int[] num[] = {{1,2},{1,2},{1,2},{1,2}} 2. int[][] num = new int[4][2] num[0][0] = 1; num[0][1] = 2; num[1][0] = 1; num[1][1] = 2; num[2][0] = 1; num[2][1] = 2; num[3][0] = 1; num[3][1] = 2; If you don't allocate let's say num[2][1] is not initialized, and then it is automatically allocated 0, that is, automatically num[2][1] = 0; 3. Below num1.length gives you rows 4. While num1[0].length gives you number of elements related to num1[0]. Here num1[0] has related arrays num1[0][0] and num[0][1] only. 5. Here we used a 'for' loop which helps us to calculate num1[i].length, and here i is incremented through a loop. */ int num1[][] = {{1,2},{1,2},{1,2},{1,2}}; int num2[][] = {{1,2},{1,2},{1,2},{1,2}}; int num3[][] = add(num1,num2); for(int i = 0; i<num1.length; i++) { for(int j = 0; j<num1[j].length; j++) System.out.println("num3[" + i + "][" + j + "]=" + num3[i][j]); } }
   }

I'll add that if you want to read the dimensions, you can do this:

int[][][] a = new int[4][3][2];
System.out.println(a.length); // 4
System.out.println(a[0].length); // 3
System.out.println(a[0][0].length); //2

You can also have jagged arrays, where different rows have different lengths, so a[0].length != a[1].length.

 int[][] myNums = { {1, 2, 3, 4, 5, 6, 7}, {5, 6, 7, 8, 9, 10, 11} }; for (int x = 0; x < myNums.length; ++x) { for(int y = 0; y < myNums[i].length; ++y) { System.out.print(myNums[x][y]); } }

Output

1 2 3 4 5 6 7 5 6 7 8 9 10 11

Your Answer

Sign up or log in

Sign up using Google Sign up using Facebook Sign up using Email and Password Submit

Post as a guest

Post Your Answer Discard

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy