In Ruby, I did:
"string1::string2".split("::")In Scala, I can't find how to split using a string, not a single character.
4 Answers
The REPL is even easier than Stack Overflow. I just pasted your example as is.
Welcome to Scala version 2.8.1.final (Java HotSpot Server VM, Java 1.6.0_22).
Type in expressions to have them evaluated.
Type :help for more information.
scala> "string1::string2".split("::")
res0: Array[java.lang.String] = Array(string1, string2)In your example it does not make a difference, but the String#split method in Scala actually takes a String that represents a regular expression. So be sure to escape certain characters as needed, like e.g. in "a..b.c".split("""\.\.""") or to make that fact more obvious you can call the split method on a RegEx: """\.\.""".r.split("a..b.c").
That line of Ruby should work just like it is in Scala too and return an Array[String].
If you look at the Java implementation you see that the parameter to String#split will be in fact compiled to a regular expression.
There is no problem with "string1::string2".split("::") because ":" is just a character in a regular expression, but for instance "string1|string2".split("|") will not yield the expected result. "|" is the special symbol for alternation in a regular expression.
scala> "string1|string2".split("|")
res0: Array[String] = Array(s, t, r, i, n, g, 1, |, s, t, r, i, n, g, 2)
