How do I select multiple fields in jq?

My input file looks something like this:

{ "login": "dmaxfield", "id": 7449977, ...
}
{ "login": "dmaxfield", "id": 7449977, ...
}

I can get all the login names with this : cat members | jq '.[].login'

but I have not been able to crack the syntax to get both the login and id?

1

4 Answers

You can use jq '.[] | .login, .id' to obtain each login followed by its id.

8

This works for me:

> echo '{"a":1,"b":2,"c":3}{"a":1,"b":2,"c":3}' | jq '{a,b}'
{ "a": 1, "b": 2
}
{ "a": 1, "b": 2
}

3

Just provide one more example here (jq-1.6):

Walk through an array and select a field of an object element and a field of object in that object

echo '[{"id":1, "private_info": {"name": "Ivy", "age": 18}}, {"id":2, "private_info": {"name": "Tommy", "aga": 18}}]' | jq ".[] | {id: .id, name: .private_info.name}" -
{ "id": 1, "name": "Ivy"
}
{ "id": 2, "name": "Tommy"
}

Without the example data:

jq ".[] | {id, name: .private_info.name}" -

.[]: walk through an array

{id, name: .private_info.name}: take .id and .private_info.name and wrap it into an object with field name "id" and "name" respectively

1

In order to select values which are indented to different levels (i.e. both first and second level), you might use the following:

echo '[{"a":{"aa":1,"ab":2},"b":3,"c":4},{"a":{"aa":5,"ab":6},"b":7,"c":8}]' \ | jq '.[]|[.a.aa,.a.ab,.b]'
[ 1, 2, 3
]
[ 5, 6, 7
]

0

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