I am trying to get the time it takes to run a command, with the output in a specific format:
time -f "%E" ls -lThis is similar to the example in the man page (and on the online man page). However when I run this command I get:
-f: command not foundIt appears as though the time command is not reading the -f as an argument, rather as the command I am trying to run.
How can I get the execution time for a command in a specific format?
2 Answers
This is because time is a bash builtin command - and the builtin doesn't support the options you're trying to use.
Try this, use the full path of time to skip the built-in and use the real one:
/usr/bin/time -f "%E" ls -l 0 Unfortunately, time is both a bash keyword and a program in /usr/bin. If you specify the full path to time like:
/usr/bin/time -f "%E" ls -lYou will get the output you were expecting.
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